Re: Re: Showing various result from a mysql query

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Hi anna,

Thanks for the suggestion, but it didn't worked, when
i try it on the browser, it ask me if i want to
download , open the file.

Any other sugg........?



 --- annA <escape2ocean@xxxxxxxxx> escribió:

> Hi Juan,
> 
> I haven't read the list for a 'few' days so I'm
> sorry if you've been 
> sweating over this, but if you haven't yet solved it
> then make sure you 
> send a
> 
> Header("Content-type:
> application/x-www-urlform-encoded");
> 
> before your
> 
> echo $rString;
> 
> annA
> 
>
----------------------------------------------------------------------------
> Subject:
> Showing various result from a mysql query
> From:
> Juan Stiller <juanstiller@xxxxxxxxxxxx>
> Date:
> Thu, 29 Sep 2005 20:11:27 +0000 (GMT)
> To:
> php-db@xxxxxxxxxxxxx
> 
> Hi, im working on a php file that its supposed to
> retrieve data from a mysql database, to send it to a
> flash animation to show the results. Thing is that
> im
> testing some modifications to the code, so if there
> is
> more than one entry, it shows all the results.
> 
> For some reason probably a mistake on the code im
> getting this output when i try the muestra.php file
> on
> the browser:
> 
>
n=1&Hora0=17:30:43&Apellido0=garofalo&Id0=6&Dia0=28&Mes0=9&Ano0=2005&Nombre0=cristian&Destinatario0=martan=1&Hora0=17:30:43&Apellido0=garofalo&Id0=6&Dia0=28&Mes0=9&Ano0=2005&Nombre0=cristian&Receptor0=marilun=1&Hora0=17:30:43&Apellido0=garofalo&Id0=6&Dia0=28&Mes0=9&Ano0=2005&Nombre0=cristian&Destinatario0=martan=1&Hora0=17:30:43&Apellido0=garofalo&Id0=6&Dia0=28&Mes0=9&Ano0=2005&Nombre0=cristian
> 
> This might not be wrong, but when i show info on the
> flash animation i get eg:
> 
> Apellido0=garofalo , i dont want to get the n=x on
> the
> output, its supposed to be just an internal thing to
> tell flash that for the variable Apellido(lastname)
> there is more than one result and then to show all
> of
> them.
> 
> 
> This is the php code:
> 
> <?php
> $conn = @mysql_connect("localhost", "blah",
> "blah23");
> 
> if (!$conn) {
> echo( "<P>No se pudo conectar " .
> "al servidor MySQL.</P>" );
> exit();
> }
> 
> if (! @mysql_select_db("llamadas") ) {
> echo( "<P>No se puede encontrar " .
> "la base de datos clientes!</P>" );
> exit();
> }
> 
> $qr = mysql_query("select * from datos");
> $nrows =
> mysql_num_rows($qr);
> $rString = "n=".$nrows;
> for ($i=0; $i < $nrows; $i++) {
> $row = mysql_fetch_array($qr);
> $rstring .= "&Id".$i."=".$row['id'];
> $rString .=
>
"&Dia".$i."=".$row['dia']."&Mes".$i."=".$row['mes']."&Ano".$i."=".$row['ano'];
> $rString .=
>
"&Hora".$i."=".$row['hora']."&Minutos".$i."=".$row['minutos'];
> $rString .= "&Receptor".$i."=".$row['receptor'].
> $rString .=
> "&Destinatario".$i."=".$row['destinatario'].
> $rString .= "&Apellido".$i."=".$row['apellido'].
> $rstring .= "&Nombre".$i."=".$row['nombre'];
> $rstring .= "&Telefono".$i."=".$row['telefono'];
> $rstring .= "&Asunto".$i."=".$row['asunto'];
> }
> echo $rString;
> mysql_free_result($qr);
> ?>
> 
> Also, i was told that including password and user to
> connect to mysql server sholdn´t be shown on the php
> file, so i have to use include_one and the file, but
> i
> don´t know exaclty the syntax, can anybody help me
> with it?
> 
> Thanks in advance.
> 


	


	
		
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