Re: newbie question on PHP & Mysql...

[Sylvain Gourvil <opensource_france@xxxxxxxx>]

Hi !

Could you do a "print_r($result)" after your mysql_query ?

Or you sure of your argv[1] ?

Sylvain Gourvil

Evert Meulie wrote:
> Hi all!
>
> I'm taking my first steps with PHP & MySQL.
>
> Can anyone give me a hint on why this would not work?
>
> *********************
>
> $result = mysql_query('SELECT SUM(AcctInputOctets), 
> SUM(AcctOutputOctets)  FROM radacct WHERE username = $argv[1] ');
> echo mysql_result($result,0), "\n";
> echo mysql_result($result,0,1);
>
> *********************
>
>
> I get: Warning: mysql_result(): supplied argument is not a valid MySQL 
> result resource
>
>
>
> Regards,
>     Evert

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