To further append the previous note,
if you want to insert the array, you need to serialize it
(www.php.net/serialize) to make the array db safe
if you want to insert the individual specific values, you will need to
implode the array with separators (and check the data in the correct order
for the field list) or you will need to supply a field list that matches the
array list to ensure the data elements are placed into the correct columns
Bastien
From: Jon Crump <jjcrump@xxxxxxxxxxxxxxxx>
To: php-db@xxxxxxxxxxxxx
Subject: pg_insert tyro question
Date: Mon, 22 Aug 2005 14:34:03 -0700 (PDT)
Being a tyro, I'm sure I'm missing something obvious about handling the
array $_POST. I hope wiser heads can point me in the right direction.
This fails:
<?php
$db = pg_connect( "dbname=foo user=bar" );
if( $db )
{
print "Successfully connected to port: " . pg_port($db) ."<br/>\n";
} else {
print pg_last_error ($db);
exit;
}
$res = pg_insert($db, 'vracore', $_POST);
if ($res) {
echo "You're a Genius";
} else {
print_r ($_POST);
exit;
}
pg_Close( $db );
?>
The connection string works fine. If I insert each field in $_POST
separately, that works fine too eg.
$value1=$_POST['value1'];
$value1=$_POST['value2'];
etc...
$query = "insert into foo (columnname1, columnname2, etc...) values
($value1, $value2, etc...);";
$result = pg_exec($db, $query);
But if I try pg_insert($db, 'foo', $_POST);
it fails. I note that print_r ($_POST) returns a list of values that
includes [addentry] => Add Entry from the submit button. Is that what's
screwing it up?
Any clues would be much appreciated.
Jon
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