I made that modification and now it doesn't update the DB at all...
Here is the code that I am using to insert that variable into my MySQL DB...
Again, my variable is defined as $rec2day = date("Y-m-d") OR $rec2day =
date("Y/m/d")
<?php
$connection = @mysql_connect("$server", "$user", "$pass") or die("Couldn't
Connect To Server.");
$db = @mysql_select_db($dbname, $connection) or die("Couldn't Select
Database.");
$sql = "UPDATE $table1 SET last_access_date=$rec2day WHERE
username='$dealer_number' AND password='$password'";
$result = @mysql_query($sql,$connection) or die("Couldn't Execute Query.");
?>
"Bruno Ferreira" <morphine@xxxxxxxxxxxxxxxx> wrote in message
news:42A9BA9F.4050406@xxxxxxxxxxxxxxxxxxx
> Chase wrote:
>
>>I have a variable:
>> $rec2day = date("Y-m-d");
>>that displays correctly when echoed to the screen, but when I write it to
>>my DB, I get the mathmatical answer to the equasion (1989 (2005-06-10)).
>>
>>What do I need to do to correct this??
>>
> Just use $rec2day= date("Y/m/d");
>
> You database system doesn't like using "-" as a separator in dates,
> thus thinking it's a minus sign and doing the appropriate math. Just use
> slashes and you'll probably be OK.
>
> -- Bruno Ferreira
> ---
> [This E-mail scanned for viruses by Declude Virus]
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