Re: changing output method

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as usual my database is in mysql
and there are lots of records available
i had wrote my script like this
$link = mysql_connect("localhost", "chintan","hellomysql")
	or die("Could not connect");
	mysql_select_db("chintan") or die("Could not select database");

	$query = "SELECT * FROM stockiestandbookingagents";
	$result = mysql_query($query) or die("Query failed");

	$i=0;
	while($i<mysql_num_fields($result))
        {
        echo (mysql_field_name($result, $i));
        print "\t";
        while ($line = mysql_fetch_array($result))
                    {
                    foreach ($line as $col_value);
                    }
        $i++;
        print "\t$col_value\n";
        }

	mysql_free_result($result);
	mysql_close($link);


but it just displays the pincode of the city only(the last column) the table structure is like below; +--------------+--------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +--------------+--------------+------+-----+---------+-------+ | CompanyName | varchar(50) | | PRI | | | | AddressLine1 | varchar(100) | YES | | NULL | | | AddressLine2 | varchar(100) | YES | | NULL | | | City | varchar(50) | YES | | NULL | | | PostalCode | varchar(50) | YES | | NULL | | +--------------+--------------+------+-----+---------+-------+

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