:( nothing On Mon, 7 Feb 2005 14:10:10 -0500, Joseph Crawford <codebowl@xxxxxxxxx> wrote: > try INNER JOIN? > > > On Mon, 7 Feb 2005 19:47:29 +0100, Zouari Fourat <fourat@xxxxxxxxx> wrote: > > that wont work :( > > and either when changing RIGHT to LEFT JOIN that wont work > > > > > > On Mon, 7 Feb 2005 13:41:01 -0500, Joseph Crawford <codebowl@xxxxxxxxx> wrote: > > > try doing this > > > > > > SELECT a.UserName FROM table1 a RIGHT OUTER JOIN table2 b ON > > > (a.UserName != b.username) > > > > > > On Mon, 7 Feb 2005 19:22:15 +0100, Zouari Fourat <fourat@xxxxxxxxx> wrote: > > > > Hello > > > > I have 2 tables with two columns in each one (cloned tables) like this : > > > > > > > > ID int(6) > > > > UserName varchar(25) > > > > > > > > and i would like to select usernames from table1 that doesnt appear in table2 > > > > so i did this : > > > > > > > > SELECT a.UserName FROM table1 a RIGHT OUTER JOIN table2 b ON > > > > (a.UserName = b.username) > > > > > > > > and that wont work, as i saw from sql joint docs, using OUTER JOIN > > > > significate that we want to join the 2 tables where the inverse of > > > > (a.UserName=b.username) is, so it's equivalent of > > > > (a.UserName<>b.username) and the LEFT option is about to show the > > > > lines from the left side table wich is a (table1) in my query > > > > > > > > why didnt that work fine ? how to resolve it and is my view on sql > > > > joins is incorect ? > > > > thanks all > > > > > > > > -- > > > > PHP Database Mailing List (http://www.php.net/) > > > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > > > > > > > > > > > > > > -- > > > Joseph Crawford Jr. > > > Codebowl Solutions > > > codebowl@xxxxxxxxx > > > > > > > -- > Joseph Crawford Jr. > Codebowl Solutions > codebowl@xxxxxxxxx > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
