Re: check out this , if block is not executing ............

[John Hicks <johnlist@xxxxxxxxxxxxxx>]

amol patil wrote:

> hallo ,
>
> entered information still not shown in table of database
>
> is below code is right ?
> form name and type values are 'submit' . then 
>
> what is wrong with this code, 
>
> <?php
>
> if(isset($_POST['submit'])) 
> {
>
> $dbh=mysql_connect ("localhost", "root") or die ('I cannot connect to 
> the database because: ' . mysql_error());
> mysql_select_db ("dollar1_allinfo");
>
> mysql_query("INSERT INTO totalinfo (Username,Password) VALUES 
> ('$loginusername','$loginpassword')")or die (mysql_error());
> }
> ?>
>  
Are you getting any error messages when you click on 'submit'? (Check 
your php log.)

Include an 'else' in your if statement (along with a debug message) so 
you can see if the 'submit' is detected.

-John

--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php