The following two scripts should help you...
in file Page1.php
<?php
echo "Hello this is the first page <br>\n";
echo "This is in file Page1.php<br>\n";
echo "<form method=\"POST\" action=\"Page2.php\">\n";
echo "\t<input type=\"submit\" name=\"submit\" value=\"Next Page\">\n";
echo "</form>\n";
echo "Note the input button must be wrapped in a form tag<br>";
echo 'Also the name attribute is the variable name that will be held in the $_POST variable';
?>
in file Page2.php
<?php echo "We're now in Page2.php<br>\n"; echo 'The submit variable is held in the $_POST variable<br>'; echo $_POST["submit"]; echo "<br>To find out what has been POSTed use the var_dump function<br>\n"; echo "<pre>\n"; var_dump($_POST); echo "</pre>\n"; ?>
graeme
amol patil wrote:
hallo ,
i wrote this , echo "Submit = $submit"; as you said.
but comments in echo statements are appearing on same pages before clicking submit button and in between same pages content .
i want these comment on new page or same page but without original content of that page
how to connect new html page in PHP after clicking submit button let simple code is like this,
<?php
echo "--Submit= $submit--";
if ($submit)
{
$dbh=mysql_connect ("localhost", "root", ) or die ('I cannot connect to the database because: ' . mysql_error());
mysql_select_db ("dollar1_allinfo");
mysql_query("INSERT INTO totalinfo (username,password,) VALUES ('$loginusername','$loginpassword',)");
echo'thank you'; echo' Hurry Up';
} ?>
THANK YOU.
"Mike S." <list.phpdb.01@xxxxxxxxxxx> wrote:
hallo ,
i have wriiten simple php script , below. created databse "dollar1_allinfo" with table 'totalinfo'
but on clicking submit button ,
information entered is not entering in database.
also, echo statements are also not displaying after submit
if ($submit)
{ $db = mysql_connect("localhost","root"); mysql_select_db("dollar1_allinfo",$db); mysql_query("INSERT INTO totalinfo (username,password,) VALUES ('$loginusername','$loginpassword')"); echo 'thank you'; echo 'So Hurry Up'; } ?>
thank you.
Because your query and echoes are within an "if" block, I'd say that $submit is evaluating to FALSE, and thus not executing the query and echoes.
Add (before the if statement):
echo "Submit = $submit";
Make sure that $submit is evaluating to TRUE.
To All Beginning Programmers ("Newbies"), or just people who want to easily debug their code: Try adding debugging statements to help you find problems. A few echoes or prints in selected locations will help identify the issue. Make sure your variables are evaluating to values that you think they should be.
If you want to keep the debugging statements in your code and just activate them when you need to see them, do something like: // near the top of your code $debug=TRUE; // and anywehere in your code if ($debug) { echo "DEBUG: Submit = $submit \n"; } // or whatever echo might help you nail down the problem. Put as many of these in your code and you can turm them ON and OFF very easily, by changing one line of code.
OR for even quicker debugging, replace $debug=TRUE; with
$debug=$_GET['debug'];
and then you can turn it on in by adding ?debug=TRUE at the end of the
URL. Example: http://www.php.net/path/my.html?debug=TRUE
or: http://www.php.net/path/my.html?debug=1
**DISCLAIMER** Using the URL method is NOT a secure way to do this!!! And I'm sure there's plenty of folks groaning out there because it is a
BIG security hole. You really would want to do this on a development
machine and network, and remove the debug code for production. That
really should go without saying.
Good luck.
:Mike S. :Austin TX USA
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