hallo,
thanks for reply, but
code is like below , i want comment in echo statemets to executed on
same page(without pages original contenti.e only echo comments )or on new pages
how to link new pages in php, after clicking submit
also.
[these first two echo statements are giving parse errors errors,unexpected '/']
<?php
echo "--$submit--";echo "--$_POST["submit"]--";
if ($submit)
{$db = mysql_connect("localhost","root");mysql_select_db("dollar1_allinfo",$db);
mysql_query("INSERT INTO totalinfo (username,password,) VALUES('$loginusername','$loginpassword')");echo 'thank you';echo 'So Hurry Up';}?>
thank you.
<graeme_foster@xxxxxxxxxxxxxxxx> wrote:
The purpose of putting the echo "Submit = $submit"; is to find out what is happening with your code. Once everything is working correctly they will be removed. What you need to find out is what is being held in the variable submit when you move from one page to the next, a point when you are expecting to enter the if($submit) clause.
I hope that clarifies it a bit.
all the best,
graeme.
amol patil wrote:
hallo, i wrote this echo "Submit = $submit"; before 'if statement' but , the sentences in echo statements are executing on same pages , showing original page with these echo statement. i want to execute , some comments and tables on same page(without original contents) or on new pages , after clicking on submit buttonwhat to do for it. thank you."Mike S." <list.phpdb.01@xxxxxxxxxxx> wrote:
hallo ,i have wriiten simple php script , below.created databse "dollar1_allinfo" with table 'totalinfo'but on clicking submit button ,information entered is not entering in database.also, echo statements are also not displaying after submit
if ($submit)
{$db = mysql_connect("localhost","root");mysql_select_db("dollar1_allinfo",$db);mysql_query("INSERT INTO totalinfo (username,password,) VALUES('$loginusername','$loginpassword')");echo 'thank you';echo 'So Hurry Up';}?>thank you.
Because your query and echoes are within an "if" block, I'd say that$submit is evaluating to FALSE, and thus not executing the query andechoes.Add (before the if statement):echo "Submit = $submit";Make sure that $submit is evaluating to TRUE.To All Beginning Programmers ("Newbies"), or just people who want toeasily debug their code:Try adding debugging statements to help you find problems. A few echoesor prints in selected locations will help identify the issue. Make sureyour variables are evaluating to values that you think they should be.If you want to keep the debugging statements in your code and justactivate them when you need to see them, do something like:// near the top of your code$debug=TRUE;// and anywehere in your codeif ($debug) {echo "DEBUG: Submit = $submit\n";}// or whatever echo might help you nail down the problem. Put as many ofthese in your code and you can turm them ON and OFF very easily, bychanging one line of code.OR for even quicker debugging, replace
$debug=TRUE; with$debug=$_GET['debug'];and then you can turn it on in by adding ?debug=TRUE at the end of theURL. Example: http://www.php.net/path/my.html?debug=TRUEor: http://www.php.net/path/my.html?debug=1**DISCLAIMER** Using the URL method is NOT a secure way to do this!!! And I'm sure there's plenty of folks groaning out there because it is aBIG security hole. You really would want to do this on a developmentmachine and network, and remove the debug code for production. Thatreally should go without saying.Good luck.:Mike S.:Austin TX USA ---------------------------------Do you Yahoo!? Yahoo! Mail - Helps protect you from nasty viruses.
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