remove the @ symbol from in front of the connect functions
@mysql_connect @mysql_select_db
Its supressing any errors that you may have...when you finish the debugging, then you can add them back in.
bastien
From: Juan Stiller <juanstiller@xxxxxxxxxxxx> To: php-db@xxxxxxxxxxxxx Subject: Fixing this code to show all variables! Date: Mon, 1 Nov 2004 10:50:12 -0300 (ART)
Hi, im trying to use this code to send a query to a mysql database, and then display the query results and put the results on variables, the problem is that i don´t know how to make it so that if there is more than one result, it uses xvariables as results are, using this script just like it is, if its more than one result it overwrite the variable with the last result. Someone told me to use an array, but i dont have any idea how.
Can you help me?
THis is the script: <?php $conn = @mysql_connect("90.0.0.2", "javier", "315/95");
if (!$conn) { echo( "<P>No se pudo conectar " . "al servidor MySQL.</P>" ); exit(); }
if (! @mysql_select_db("clientes") ) { echo( "<P>No se puede encontrar " . "la base de datos clientes!</P>" ); exit(); }
// Request all data $result1 = mysql_query("select * from clientesnuevos");
print "Results="; echo "<h1>Clientes agregados:</h1><br>";
while($row=mysql_fetch_array($result1, MYSQL_ASSOC)) { echo "&Id={$row['id']}"; echo "&Apellido={$row['apellidoclientesnuevos']}"; echo "&Nombre={$row['nombreclientesnuevos']}"; echo "&Dni={$row['dniclientesnuevos']}"; echo "&Telefono={$row['telefonoclientesnuevos']}"; echo "&Dia={$row['diacitaclientesnuevos']}"; echo "&Mes={$row['mescitaclientesnuevos']}"; echo "&Ano={$row['anocitaclientesnuevos']}"; echo "&Hora={$row['horacitaclientesnuevos']}"; echo "&Minutos={$row['minutoscitaclientesnuevos']}"; echo "&Abogado={$row['abogadoclientesnuevos']}"; echo "&Nombre={$row['nombreclientesnuevos']}"; echo "&Asunto={$row['asuntoclientesnuevos']}"; echo "&Donde={$row['dondeclientesnuevos']}"; } mysql_free_result($result1); ?>
Thanks Juan
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