$query = "SELECT * from user where name=\'$userid\' and pass=password(\'$password\')"
Alternatively, you can concatenate the expanded variables.
$query = "SELECT * from user where name='".$userid."' and pass=password('".$password."')"
Good luck, Doug
Arne Essa Madsen wrote:
I have the following problem:
This one does not work:
$query = "SELECT * from user where name='$userid' and pass=password('$password')";
$result = mysql_query($query, $link);
$num_rows = mysql_num_rows($result);
I get this error message:
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in c:\wamp\www\fs1812_new\authmain.php on line 18
This one works OK: $query = "SELECT * FROM user"; $result = mysql_query($query, $link); $num_rows = mysql_num_rows($result);
What is wrong and how can I use mysql_num_rows when the query include "WHERE"
A fast response will be very much appreciated.
Arne Essa Madsen;
arne@xxxxxxxxxxxxxxxxxx
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