RE: Changing this php code to show multiple variables!

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Another option might be to place all the elements of each value (ie all first names) into a csv or other characters separated string and then use the split command to separate out the elements into an actionscript array

hth

bastien


From: "Norland, Martin" <Martin.Norland@xxxxxxxxxx>
Reply-To: <php-db@xxxxxxxxxxxxx>
To: <php-db@xxxxxxxxxxxxx>
Subject: RE:  Changing this php code to show multiple variables!
Date: Wed, 20 Oct 2004 12:10:42 -0500

I don't pretend to know flashes interface, as I said before - but instead of naming the variables differently - you should be able to pass them in an array.

&Lastname0=craw&Firstname0=david&Lastname1=Zarlanga&Firstname1=John
becomes
&Lastname[]=craw&Firstname[]=david&Lastname[]=Zarlanga&Firstname[]=John

Assuming flash accepts the parameters in this form. You'll want to make sure you emit every variable each time, otherwise your data sets will get out of sync (emit them even if they're blank) - but I still say there surely must be a better way to be populating this data.

http://actionscript-toolbox.com/samplemx_php.php

Seems to be an introductory that may be of some use, found just by googling for 'flash php mysql'.

- Martin Norland, Database / Web Developer, International Outreach x3257
The opinion(s) contained within this email do not necessarily represent those of St. Jude Children's Research Hospital.



-----Original Message----- From: Juan Stiller [mailto:juanstiller@xxxxxxxxxxxx] Sent: Wednesday, October 20, 2004 11:27 AM To: php-db@xxxxxxxxxxxxx Subject: Changing this php code to show multiple variables!


Hi, i´ve got this php code that sends a query to a mysql server, and when it gets the query results, it send it to a flash movieclip, everything works fine when i´ve got only one entry on the database, but when there´s more than one enrty, the variable is overwritten and as reslt, it shows only one entry i was told that i must create a function to to name multiple variables, so the result might be:

&Lastname0=craw&Firstname0=david&Lastname1=Zarlanga&Firstname1=John

So here it is the php code:

<?php
$conn = @mysql_connect("***", "***", "***");

if (!$conn) {
echo( "<P>No se pudo conectar " .
"al servidor MySQL.</P>" );
exit();
}

if (! @mysql_select_db("clientes") ) {
echo( "<P>No se puede encontrar " .
"la base de datos clientes!</P>" );
exit();
}

// Request all data
$result1 = mysql_query("select * from
clientesnuevos");

print "Results=";
echo "<h1>Clientes agregados:</h1><br>";

while($row=mysql_fetch_array($result1, MYSQL_ASSOC))
{
echo "&Id={$row['id']}";
echo "&Apellido={$row['apellidoclientesnuevos']}";
echo "&Nombre={$row['nombreclientesnuevos']}";
echo "&Dni={$row['dniclientesnuevos']}";
echo "&Telefono={$row['telefonoclientesnuevos']}";
echo "&Dia={$row['diacitaclientesnuevos']}";
echo "&Mes={$row['mescitaclientesnuevos']}";
echo "&Ano={$row['anocitaclientesnuevos']}";
echo "&Hora={$row['horacitaclientesnuevos']}";
echo "&Minutos={$row['minutoscitaclientesnuevos']}";
echo "&Abogado={$row['abogadoclientesnuevos']}";
echo "&Nombre={$row['nombreclientesnuevos']}";
echo "&Asunto={$row['asuntoclientesnuevos']}";
echo "&Donde={$row['dondeclientesnuevos']}";
}
mysql_free_result($result1);
?>

Can anyone help me with this?

Thanks
Juan

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