Just to confirm,
This is what I'm going to start with:
//base sql statement
$sql = "select * from jobs where record_deleted = 'NO'
";
if (isset($_POST['states'])){
//check to see if the states is an array
// multiple items or just one
if (is_array($_POST['state']))
$sql .= "state='".implode("' OR state='",
$_POST['state'])."'";
}else{
//$_POST['state'] is not an array
$sql .= "state = '".$_POST['state']."' ";
}//end if
if (isset($_POST['job'])){
if (isset($_POST['state'])){ $sql .= " AND "; }
//add in the AND if the state is set
//check to see if the states is an array
//multiple items or just one
if (is_array($_POST['state']))
$sql .= "state='".implode("' OR state='",
$_POST['state'])."'";
$sql .= ")";
}else{
$_POST['job'] is not an array
$sql .= "job = '".$_POST['job']."' ";
}
//end if
?>
--- "Ford, Mike" <M.Ford@xxxxxxxxxxxxxx> wrote:
> > -----Original Message-----
> > From: Stuart Felenstein
> [mailto:stuart4m@xxxxxxxxx]
> > Sent: 22 September 2004 16:45
> >
> > --- "Ford, Mike" <M.Ford@xxxxxxxxxxxxxx> wrote:
> >
> > > > if (is_array($_POST['state'])){
> > > > $sql .= "(";
> > > > $x = 0;
> > > > foreach ($_POST['state'] as $state)
> > > > if ($x == 0){
> > > > $sql.= "state = '$state' ";
> > > > $x=1;
> > > > }else{
> > > > $sql .= " OR state = '$state' ";
> > > > }
> > > > $sql .= ")";
> > >
> > > PHP has the very nice implode function to make
> this
> > > much easier:
> > >
> > > $sql = "state='".implode(' OR state=',
> $_POST['state'])."'";
> > >
> > > (If your database supports the IN operator, this
> is
> > > probably even better:
> > > $sql = "state IN ('".implode("','",
> $_POST['state'])."')"; )
> >
> > Sorry, cause I know this is probably a stupid
> > question, but what block of code does the implode
> > statement replace ?
>
> Everything inside the if(is_array()). Ummm, that
> should probably still be a
> .= operator, then. There's also some quotes missing
> in the original
> version, so:
>
> if (is_array($_POST['state']))
> $sql .= "state='".implode("' OR state='",
> $_POST['state'])."'";
>
> Cheers!
>
> Mike
>
>
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