On Mon, 23 Aug 2004 17:06:40 -0700, Ben Galin <news@xxxxxxx> wrote: > Hello, > > Regarding this code: > [PHP code] > // This works > $name="name"; > $table="mytable"; > $mysql_connect("localhost","","") or die("Error: ".mysql_error()); > $mysql_select_db("mydb") or die("Error: ".mysql_error()); > $mysql_query("INSERT INTO $table (`id`,`name`) VALUES ('','$name')"); > [/PHP code] > > I want to define() TABLE as a constant instead of using the variable > $table > > [PHP code] > // This runs without an error but does *not* insert a new row > $name="name"; > define("TABLE", "mytable"); > $mysql_connect("localhost","","") or die("Error: ".mysql_error()); > $mysql_select_db("mydb") or die("Error: ".mysql_error()); > $mysql_query("INSERT INTO TABLE (`id`,`name`) VALUES ('','$name')"); > [/PHP code] > > Changing the query line to > $mysql_query("INSERT INTO `TABLE` (`id`,`name`) VALUES ('','$name')"); Well, of course PHP isn't going to change your strings. That would be a bit intrusive and make some things real hard to do. C won't even do this. Here's what you want: $mysql_query('INSERT INTO `'.TABLE.'` (`id`,`name`) VALUES ("","'.$name.'")'); > or > $mysql_query("INSERT INTO 'TABLE' (`id`,`name`) VALUES ('','$name')"); > has no effect. > > I also tried to > define("TABLE", "`mytable`"); > which, too, didn't work. > > Would appreciate any advice, > Ben > -- DB_DataObject_FormBuilder - The database at your fingertips http://pear.php.net/package/DB_DataObject_FormBuilder paperCrane --Justin Patrin-- -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php