You can use something like
$articleDate= date ("Y-m-d 00:00:00",strtotime($day ." " . $month . " "
. $year));
If $day = 10 and $month = "January" and $year = 2004
then $articleDate will be set to "2004-01-10 00:00:00"
Then you can insert $articleDate into a datetime field in mysql.
"Irm Jr" <irmjr@xxxxxxxx> wrote in message
news:B4A64F3A0C84B346BEAB2513306F10FC051CA9@xxxxxxxxxxxxxxxxxxxxxxx
Hi all, currently I have a form which prompts for the user to choose a
date. The dropdown lists are stored into variables:
$month //e.g. January, February, ...
$day //e.g 1 - 31
$year //e.g. 2004 (four digits)
then combined into
$articleDate
How can I manipulate this variable to be in such a format that I can
insert the information into a DATE column in a mySQL database.
Dates are a bit of a mystery to me as PHP and MySQL handle them
differently. Your help is appreciated.
Thanks
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