Re: problem....

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Just from looking at it, it seems to be because you are redefining a
variable, which destroys it, then calling for a mysql resource that has
been destroyed. What is the error?

I can't gaurantee that that is what is happening.

Cole

> why doesn't this work:
> $pic=mysql_query('SELECT     Rune, username FROM         RuneRunner
> RuneRunner_1 WHERE     (User_ID = 3)',$connection);
> $pic=mysql_fetch_array($pic);
>
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