hmm... what about something like this?? echo "<select name=\"dropdown\">; $query = "select code, name from table"; $result = mysql_query($query); while($array = mysql_fetch_array($result)) { echo "<option value=\"".$array["code"]."\">".$array["name"]."</option>"; } echo "</select>"; hth ----- Original Message ----- From: "Cole Ashcraft" <cole.ashcraft@xxxxxxxxxxxxxxxxxx> To: <php-db@xxxxxxxxxxxxx> Sent: Friday, June 18, 2004 7:50 AM Subject: Dropdown menus from DB query > How would you create a drop down menu from a database query? I have > figured how to do it with one field, but how could it be done with a > system where the value is different than the displayed value (ie. > numerical code as the value, name displayed)? > > Thanks, > Cole -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php