Ciao..hi, i would suggest to embed the html code in php like this: <?php $_your_variable=$row["imgid"]; echo "<a href=\"../images/image.php?img=$_your_variable\" target=\"_blank\" onClick=\"window.open(this.href, this.target, \'width=200,height=250\'); return false;\"><img SRC=\"../preview.jpg\" ALT=\"Click to look at the picture you are charging\" border=\"0\"></a>"; ?> If it works let me know , bye Francesco Basile ______________________________________________________________________ "Alessandro Folghera" <info@xxxxxxxxxxx> ha scritto nel messaggio news:40A257AF0010BE1E@xxxxxxxxxxxxxxxxxxxxx > Hi, > > I have developed a news system .. I can select to insert an image into the > articles. > > The function to extract the image calling them by the "imgid" of images > table is the following: > > function getImm() { > ?> > <select name="image"> > <? > connect(); > $sql = "select * from images"; > $result = mysql_query($sql); > while($row = mysql_fetch_array($result)) { > printf("<option value=\"%s\">%s</option>", $row["id_img"], $row["imgid"]); > } > ?> > </select> > <? > > I'd like to be able to see the image before to publish the piece of news. > > I think about a window pop up with java in order to create a preview of the > image. The code follows: > > <a href="../images/image.php?img=XXXXXXXXXX" target="_blank" > onClick="window.open(this.href, this.target, 'width=200,height=250'); > return false;"><img SRC="../preview.jpg" ALT="Click to look at the picture > you are charging" border="0"></a> > > The problem is that I can't pass the "imgid" to the href inspite of the > XXXXXXXX > > May someone tell me how to pass the id number in order to show me the image > or how may I solve the trouble? > > I hope someone will help me ... > > Sincerely, > Alexander -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php