----- Original Message -----
From: "Rachel Rodriguez" <email2rachel2003@xxxxxxxxx>
To: <php-db@xxxxxxxxxxxxx>
Sent: Friday, April 23, 2004 3:55 AM
Subject: assigning variables after one-to-many query
> Hi!
>
> I have a one-to-many relationship between two tables
> (table1 and table3) with a "linking" table between
> them (table2):
>
> table1: table2
> +---+--------+ +---+--------+
> |id | f_name | |id | emailID|
> +---+--------+ +---+--------+
> | 1 | bill | | 1 | 1 |
> | 2 | john | | 1 | 4 |
> | 3 | diana | | 1 | 3 |
> | 4 | victor | | 2 | 2 |
> | 5 | renata | | 4 | 5 |
> +---+--------+ +---+--------+
>
> table3
> +--------+-----------------+
> |emailID | email |
> +--------+-----------------+
> | 1 | bill@xxxxxxxxxxx|
> | 2 | diana@xxxxxxxxx |
> | 3 | bill@xxxxxxxxx |
> | 4 | bill@xxxxxxxxxx |
> | 5 | vic@xxxxxxxxxxx |
> +--------+-----------------+
>
maybe think again about your tables structure?
seems like a mess to me.
> I would like to write a query that matches table1.id
> with records
> from table3.emailID via the linking table (table2) and
> then
> assign each match to a variable.
>
> Here is what I have:
>
> $query = "SELECT t3.email
> FROM table3 AS t3
> LEFT JOIN table2 AS t2
> ON (t3.emailID = t2.emailID)
> LEFT JOIN table1 AS t1
> ON (t2.id = t1.id)
> WHERE t1.id = 1";
>
> $result = @myql_query($query, $db_connection);
>
> $num = mysql_num_rows($result);
>
> $email1 = "";
> $email2 = "";
> $email3 = "";
>
> if ($num > 0)
> {
> while ($row = mysql_fetch_array($result))
> {
> // do something here to assign
> // $email1 = $row[email] and
> // $email2 = $row[email], etc.
> }
> }
>
> Of course, the problem I am having is as I am going
> through the "while" loop, I am assigning $email1,
> $email2, and so on the
>
> same e-mail address.
>
> I would like to get: $email1 = bill@xxxxxxxxxxx,
> $email2 = bill@xxxxxxxxxx, and $email3 =
> bill@xxxxxxxxxx
what i would do is add it into an array:
$emails = Array();
while ($row = mysql_fetch_array($result,MYSQL_NUM))
{
$emails[] = $row[0];
}
then u have an array with :
$emails[0] = bill@xxxxxxxxxxx
$emails[1] = bill@xxxxxxxxxx
etc...
>
> I would prefer to do that rather than what I have seen
> in most examples which is similar to the following:
>
> // snippet of code
>
> while ($row = mysql_fetch_array($result))
> {
> echo"Bill's email is $row[email].";
> }
>
> // end of snippet
>
> Any assistance is greatly appreciated.
>
> Thanks,
> Rachel
>
>
>
>
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