$keywords = str_replace(' ','%',$keywords);
select * from table where data like "%keywords%";
-----Original Message-----
From: Hadi [mailto:support@xxxxxxxxxxxxxxxxx]
Sent: 12 December 2003 13:21
To: php-db@xxxxxxxxxxxxx
Subject: anyone trickier than 'LIKE' ?
Hi all,
I have this data (eg.) "..........big fat buddy......." on the database . If
a person enter "big buddy" in the search form , the ".......big fat
buddy........." data will not be found . Any suggestion ? Thanks in advance.
select * from table where data like "%keywords%";
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