Putting more than one table in the FROM clause means tables are joined, then at least following problems could arise:
- using WHERE clause you can have empty recordset returned and then COUNT conflicts with it because there is actually no any data to be returned;
- joining two (or more) tables without using aliases to the equally named columns in the SELECT/WHERE/COUNT clauses will produce error message instead of expecting data;
- COUNT(*) wont work if u have equal table names in the tables;
If you give us some more detail description of the tables then it will be easier to find where the problem is
Boyan --
John W. Holmes wrote:
Mark Gordon wrote:
Yes, query is definitely working without COUNT(*). Even in the most stripped down form, the query fails:
$sql = "SELECT COUNT(bandid), genre FROM bands, genre"; $result=mysql_query($sql); while ($gen=mysql_fetch_row($result)) { echo $gen[1]; }
Fails how? If it echos zero, it's not failing; your query just isn't returning any rows (regardless whether you think it should or not).
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