Some times parse errors aren't in the line the interpreter says. Looking at the code you sent I don't see the error but if your original code is in a biger file try looking if the brackets {} or parenthesis of all the code are balanced. "Scott V Nipp" <sn4265@sbc.com> escribió en el mensaje news:E9E12A91DAEB374493D8501FE29552FDC0DD28@txdlls2msgusr11.itservices.sbc.c om... > I keep receiving a parse error every time I try and view the page I > am working on. I am developing this very simple application in DreamWeaver > MX 2004. Here are lines 3-16: > > <?php > mysql_select_db($database_Prod, $Prod); > $query_Host = "SELECT Name FROM systems"; > $Host = mysql_query($query_Host, $Prod) or die(mysql_error()); > $row_Host = mysql_fetch_assoc($Host); > $totalRows_Host = mysql_num_rows($Host); > > mysql_select_db($database_ProdUsers, $ProdUsers); > $query_UserMod = "SELECT shell, home_dir FROM modification"; > $UserMod = mysql_query($query_UserMod, $ProdUsers) or die(mysql_error()); > $row_UserMod = mysql_fetch_assoc($UserMod); > $totalRows_UserMod = mysql_num_rows($UserMod); > > ?> > > I am simply attempting to pull data from two separate tables in two > separate databases. Every time I try to view my work, I am getting a parse > error on the 'mysql_select_db($database_ProdUsers, $ProdUsers);' regardless > of whether this is the first or second mysql_select_db. I imagine that I am > simply doing something obviously wrong here. Please help. Thanks. > > > Scott Nipp > Phone: (214) 858-1289 > E-mail: sn4265@sbc.com > Web: http:\\ldsa.sbcld.sbc.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php