> How do you pass by reference? I tried > $var = myFunction(&$var1, &$var2); > but it gave me a warning saying that pass by reference is depreciated > Call time pass by refrence is depreciated you should read the manual to see how it should be done. http://www.php.net/manual/en/language.references.pass.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php