Re: mysql field not resolving comaparison condition for zip code locator

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Thanks for the suggestion but the quotes didn't make a difference I
submitted the sql though php myadmin that takes care of the quote syntax
"Peter Beckman" <beckman@purplecow.com> wrote in message
20030923143903.K1144@thermonuclear.org">news:20030923143903.K1144@thermonuclear.org...
>
> On Tue, 23 Sep 2003, AdminHMO wrote:
>
> > I am having trouble implementing a zip code locator program. All of the
> > functions work correctly but the $sql variable.
>
> Try putting the SQL in quotes:
>
>  $sql = "SELECT City FROM ZIPCodes WHERE Latitude <= 122.02671343318 AND
>  Latitude >= 121.96888656682 AND Longitude >= 37.617091284671 AND
Longitude
>  <= 37.508048715329";
>
> > The problem occurs by using the latitude argument as a comparison. The
first
> > latitude argument works but when the second
> > latitude argument is added the query returns no data. Here is an example
of
> > the $sql variable being used.
> >
> > $sql=SELECT City FROM ZIPCodes WHERE
> >    Latitude <= 122.02671343318
> >               AND Latitude >= 121.96888656682
> >    AND Longitude >= 37.617091284671
> >    AND Longitude <= 37.508048715329;
> >
> > This is the format recommended by the zip code locator develper for the
sql
> > argument. There must be some logical way
> > to present this to the mysql database that will perform the latitude and
> > longitude comparison and retun the proper results.
> > A suggestion was making sure that the field is a numberic string type. I
> > used "Float", "Decmial", "Double" and "CHAR" the result was the same.
Please
> > help!
>
> --------------------------------------------------------------------------
-
> Peter Beckman                                                  Internet
Guy
> beckman@purplecow.com
http://www.purplecow.com/
> --------------------------------------------------------------------------
-

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