RE: Extracting result - unknown number of fields

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OK, please ignore, I believe I've found the answer in the manual notes:

$query="your SQL";
$result=mysql_query($query) or die("Query ($query) sucks!");
$fields=mysql_num_fields($result);

echo "<table>\n<tr>";
for ($i=0; $i < mysql_num_fields($result); $i++) //Table Header
{ print "<th>".mysql_field_name($result, $i)."</th>"; }
echo "</tr>\n";
while ($row = mysql_fetch_row($result)) { //Table body
echo "<tr>";
for ($f=0; $f < $fields; $f++) {
echo "<td>$row[$f]</td>"; }
echo "</tr>\n";}
echo "</table>
http://www.php.net/manual/en/function.mysql-num-fields.php

-----Original Message-----
From: Dillon, John [mailto:JDillon@cantor.co.uk]
Sent: 14 August 2003 17:05
To: php-db@lists.php.net
Subject: RE:  Extracting result - unknown number of fields


..but even if I can get the names and number of fields during 'run-time',
how do I make the following statement applicable to a variable number of
fields:

while(list($a,$b...)= mysql_fetch_array($result))

or is there another way to extract which would work?

John

-----Original Message-----
From: CPT John W. Holmes [mailto:holmes072000@charter.net]
Sent: 14 August 2003 16:29
To: Dillon, John; php-db@lists.php.net
Subject: Re:  Extracting result - unknown number of fields


From: "Dillon, John" <JDillon@cantor.co.uk>

> While doing a cross tabulation, I've got a query which gives me a variable
> number of fields:

Maybe mysql_num_fields() and mysql_field_name() will be of use, here? Check
the manual..

---John Holmes...


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