Re: Re: PHP help

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Surely this will fail because $login has not been defined, by use of 
something like

$login = $_REQUEST['login'];

I tried the naked code as given, and (as expected) got an error - 
undefined variable - $login 

I was under the impression that had to be done for all 'incoming', if it 
was to be used for anything.....

Terry Riley

----------Original Message---------  

> 
>   $query="INSERT INTO login VALUES ('$login')";
> 
> have fun
> 
> 
> Bill Pilgrim wrote:
> > My System:  
> > Windows 98
> > Apache 1.3.27
> > PHP 4
> > mysql
> > 
> > Hello all, I am a PHP beginner and was wondering if I could get some 
> > help from some of the more experienced on this list.  I have been 
> trying to use an html form (with textboxes, radio buttons, and 
> textareas) to input data into a mysql database.  I am able to connect 
> fully with the database and am able to create tables in it, but when I 
> try to input information into the tables nothing happens. ever...  I 
> don't really know what to do from here, but I assume that a 
> configuration is not set properly between mysql, apache, windows, or 
> php.  I really don't know what it could be.  My code is here and I have 
> tried to simplify the form in order to get it working, so here is my 
> barebones code that hopefully has some errors:
> > HTML:
> > <html>
> > <head>
> > <title>Simplify</title>
> > </head>
> > <body>
> > <form action="addform.php" method="post">
> > Login: <input type="text" name="login">
> > <input type="submit">
> > </form>
> > </body>
> > </html>
> > 
> > PHP file called "addform.php":
> > 
> > <?
> > 
> > $user="chris";
> > $database="test";
> > mysql_connect(localhost,$user);
> > @mysql_select_db($database) or die("unable to select database");
> > $query="INSERT INTO login VALUES ("'$login')";
> > mysql_query($query);
> > mysql_close();
> > ?>
> > 
> > Login is the name of the table on the database named test.
> > 
> > I stopped using a password because it wouldn't let anything work even 
> > table creation when I tried to use a password.  Any help that anyone 
> could give would be greatly appreciated; there is probably some 
> grievious error in this script.  Thanks, Chris

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