It's so easy in MySQL, but if I do it there I have to do a separate query for each city - not the worst thing, there are only about 5, but it doesn't seem very efficient.
-Lisi
At 09:57 AM 6/18/03 +0200, Snijders, Mark wrote:
hi,
i'm not sure if I get the point, but can't you do it like this:
for the minutes: (but when minutes is smaller as 40 you will get a negative digit, so maybe also use the hours with it.....
mktime (0,sunset_a[minute]-40,0,0,0,0);
tell me if it works otherwise i can look for another solution
-mark-
-----Original Message----- From: Lisi [mailto:lists@shemeshdirectory.co.il] Sent: woensdag 18 juni 2003 10:46 To: PHP-DB Subject: mktime to subtract minutes (was Time without seconds)
I realized I need to do some processing on the time after it's retrieved, so I decided to retrieve hours and minutes separately and then subtract the necessary time with PHP. Each city has sunset times for each day stored in the database, in a datetime field. I retrieve all cities and times for a today's date, and then loop through the results to display them in a table. Depending on which city it is, though, I need to subtract a certain amount of time - 18 minutes for one, 20 minutes for another, and 40 for the third.
I thought the best way to do this would be to use a combination of mktime and date, and this works for adding an hour if daylight savings time is in effect.
$hour = $dst ? $sunset_a[hour]+1 : $sunset_a[hour]; $time = mktime ($hour,$minute,0,1,1,2003); $time = date("G:i", $time);
But how do I do this for minutes? If I do this: $minute = $sunset_a[minute]-40;
and plug that into the mktime line above, I get the wrong answer: 24:00 - 40, not $sunset_a[minute] - 40.
Is there no easy way to subtract time n PHP, like in MySQL with DATE_SUB? Or am I missing something easy with mktime?
TIA,
-Lisi
-- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
-- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
