I don't know how you're calling the second run through the array, but the
following might work and is a bit more elegant than a copy/paste job.
for ( $i=0; $i<2; i++ ) {
while($rows = mysql_fetch_array($h_navmenu))
{
$navmenu = $rows["navmenu"];
echo $navmenu . "<br>";
}
mysql_data_seek($result ,0);
}
Edward Dudlik
Becoming Digital
www.becomingdigital.com
----- Original Message -----
From: "Jason McCormack" <mccormack_j@hotmail.com>
To: <php-db@lists.php.net>
Sent: Tuesday, 20 May, 2003 00:24
Subject: Re: PHP and Mysql Queries
Peter,
Thank you very much. Exactly what I was looking for.
Jason
Peter Lovatt wrote:
> hi
>
> mysql_data_seek($result ,0) will move the result pointer to the beginning of
> the result set
> then
> while(.....)
> {
> ......
> }
>
> as before
>
> Peter
> -----Original Message-----
> From: Jason McCormack [mailto:mccormack_j@hotmail.com]
> Sent: 20 May 2003 05:01
> To: php-db@lists.php.net
> Subject: PHP and Mysql Queries
>
>
> Hello All,
>
> I have a script that runs a mysql query against my database. I need to
> loop through the array of data twice. My script runs the first loop as
> expected but when it runs the second loop I get no data returned. Is
> there a way to be able to loop through the same data result set twice
> without having to take the data set and put it into a different array
> variable. Any ideas are greatly appreciated.
>
> Thanks,
> Jason
>
> Code Block
>
> $q_navmenu = "select navmenu,count(navmenu) as count from sitenav where
> navgroup = 'toc' and active = 'T' group by navmenu order by navmenu";
> $h_navmenu = mysql_query($q_navmenu,$connect);
>
> while($rows = mysql_fetch_array($h_navmenu))
> {
> $navmenu = $rows["navmenu"];
>
> echo $navmenu . "<br>";
> }
>
>
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>
>
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