> I'm having trouble creating an insert form...the problem is that I > don't have only one table, but 5 or 6...so I should insert in ex. > $table where $ID. > also the form needs dynamically generate in relation to the table I > choose...I mean it depends on how many column a table has that the form > has the correspondent number of field...the Id and created are auto(so > no field). Each database has a way to get the auto created number. With MySQL, it's mysql_insert_id(). ---John W. Holmes... PHP Architect - A monthly magazine for PHP Professionals. Get your copy today. http://www.phparch.com/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php