Re: Warning: Unable to jump to row...

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Hi Ben

Comments inline ....

On 31 Mar,2003 at 13:46 Benjamin Trépanier wrote:

<snip>
> border="0">
>     
>     <?
>     
> $i!=$id_news_
> $id    = mysql_result($req,$i,"id");
> $titre = mysql_result($req,$i,"titre");
> $date       = mysql_result($req,$i,"date");
> $heure      = mysql_result($req,$i,"heure");
> $heure      = str_replace(":","h",$heure);
> $news       = stripslashes(trim(mysql_result($req,$i,"news")));
> 
> 
</snip>

You should try using one of mysql_fetch_array() / mysql_fetch_row() to step through the recordset.  Something along the lines of

<?php

while ($data = mysql_fetch_array($req)) {
	// handling code for each row here using references like this

	$id = $data["id"];
	$titre = $data["titre"];

	echo "<tr><td>$id</td><td>$titre</td></tr>\n";  
	// \n above to keep the html source reasonably tidy
}
	
?>


<snip>
> ?>
> 
> I want that my script show the content of the rows corresponding to my
> Variable called: Id_News_
> 
> So the variable is moving well but when the scirpt is running and go to
> display the row  this code happend:
> 
> Warning: Unable to jump to row number X
> 
</snip>

Hope this helps.

-- 
Ronan
e: ronan@thelittledot.com
t: 01903 739 997
w: www.thelittledot.com

The Little Dot is a partnership of
Ronan Chilvers and Giles Webberley

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