Re: using a variable as values in an array

[Charles Kline <ckline@rightcode.net>]

Hmm... that is not quite it. Here is a better example:

Here is how I would define default values for a checkbox in 
HTML_QuickForm;

$defaultValues['ichkABC']   = array('A'=>true,'B'=>true);
$form->setDefaults($defaultValues);

The checkboxes are defined later like this:

$checkbox[] = &HTML_QuickForm::createElement('checkbox', 'A', null, 
'A');
$checkbox[] = &HTML_QuickForm::createElement('checkbox', 'B', null, 
'B');
$checkbox[] = &HTML_QuickForm::createElement('checkbox', 'C', null, 
'C');
$checkbox[] = &HTML_QuickForm::createElement('checkbox', 'D', null, 
'D');
$form->addGroup($checkbox, 'ichkABC', 'ABCD:', array('&nbsp;', '<br 
/>'));

So what I am trying to do is built that array that gets passed to: 
$defaultValues['ichkABC']   =

If I can create a variable that contains the array that is fine too. 
the values 'A' or 'B' as in the above example will be the values in 
quotes as I get them from my table query.


thanks
charles



On Monday, March 31, 2003, at 04:52 PM, Jennifer Goodie wrote:

> > $mystring;
> > foreach ($sth_opt as $thekey => $thevalue){
> > 	$mystring .= "'".$thevalue."'=>true, ";
> > }
> > $defaultValues['ib_article']   = array($mystring);
>
> Try this ...
>
> foreach ($sth_opt as $thekey => $thevalue){
> 	$defaultValues['ib_article'][$thevalue] = 'true';
> }
>
> I'm not sure if the indices line up exactly with what you had in mind, 
> but
> I'm confident you can play with it to get what you want.
>
>
> -----Original Message-----
> From: Charles Kline [mailto:ckline@rightcode.net]
> Sent: Monday, March 31, 2003 1:49 PM
> To: Jennifer Goodie
> Cc: php-db@lists.php.net
> Subject: Re:  using a variable as values in an array
>
>
> Here is more details. Thanks for the reply.
>
> I am using HTML_QuickForm (pear) to create my forms. In order to set
> the default state of some of the elements (checkboxes in this case) I
> need to pass an array as the value to QuickForm.
>
> This array needs to be in the format of this:
>
> array('30'=>true, '29'=>true) where the 30 and 29 are the values that
> are coming back from my query. This could return up to 50 records.
>
> This is what I was trying, but it isn't woring:
>
> $mystring;
> foreach ($sth_opt as $thekey => $thevalue){
> 	$mystring .= "'".$thevalue."'=>true, ";
> }
>
>
> On Monday, March 31, 2003, at 04:32 PM, Jennifer Goodie wrote:
>
> > Instead of building a string in your loop do the assignment in the 
> > loop
> > I have no idea what is being pulled from where, so I can't really give
> > a
> > good example
> >
> > -----Original Message-----
> > From: Charles Kline [mailto:ckline@rightcode.net]
> > Sent: Monday, March 31, 2003 1:25 PM
> > To: php-db@lists.php.net
> > Subject:  using a variable as values in an array
> >
> >
> > I am trying to build an array from the results of a query on a mySQL
> > table.
> >
> > I am using a loop to create this string in a variable $mystring:
> >
> > '30'=>true, '20'=>true
> >
> > I then need to use it like this:
> >
> > $defaultValues['ib_article']   = array($mystring);
> >
> > It isn't working. I am sure there is a better method, can anyone point
> > me in the right direction?
> >
> > thanks
> > charles
> >
> >
> > --
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