I have a PHP<->MySQl-problem. I would be very greatful if anyone would help me. I am - with the following code - trying to get results from a database. The problem isn't recieving the results, it's where i get the results. All the information is placed far down on the site, not in top. If you're having problems understanding what I'm trying to say, I don't blame you. I don't really understand either. The easiest thing would be for you to check the code, then got to the site link below to see for yourselves. Thanks //Anders link: http://medlem.spray.se/tippafotboll/full.php code: <?php if (!($dblink = mysql_connect("localhost", "*****", "*****"))) //Databaskoppling mot server. { print("Kunde inte skapa koppling mot databasen."); } if (!(mysql_select_db("tippafotboll_se_db", $dblink))) { print("Kunde inte välja databasen."); } else { //Array $getarray = mysql_db_query("tippafotboll_se_db", "SELECT * FROM tblTeams"); while($arrayrow = mysql_fetch_array($getarray)) { $team[$arrayrow["id"]] = $arrayrow["teamname"]; } print("<html><head></head><body>"); print("<table width='50%' border='1'>\n"); print("<form name='newbet' method='post' action='insertbet.php'>\n"); //SQL-query $row = mysql_db_query("tippafotboll_se_db", "SELECT * FROM tblGames ORDER BY date"); while($games = mysql_fetch_object($row)) { $hid = $games->home; $aid = $games->away; $gameid = $games->id; print("<tr><td> $team[$hid] - $team[$aid] </td>\n"); print("<td><input type='radio' name='game$gameid' value='1'> </td>\n"); print("<td><input type='radio' name='game$gameid' value='x'> </td>\n"); print("<td><input type='radio' name='game$gameid' value='2'></td><br></tr>\n"); } print("<tr><td><input type='submit' value='skicka in rad'></form></tr></table></body></html>\n"); } //Databaskopplingen stängs mysql_close(); ?> -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php