RE: MySQL result resource

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It means your query failed... it always means your query failed for some
reason (unless you typo a variable name...). Learn to use mysql_error()
in conjunction with mysql_query(). Also, like I said before,
mysql_db_query() is depreciated, you should be using mysql_query().

---John W. Holmes...

PHP Architect - A monthly magazine for PHP Professionals. Get your copy
today. http://www.phparch.com/

> -----Original Message-----
> From: Addison Ellis [mailto:addison@bellsouth.net]
> Sent: Wednesday, January 29, 2003 10:02 PM
> To: php-db@lists.php.net
> Subject:  MySQL result resource
> 
> hello,
> 	i have a new issue... :-)
> 	i am getting:
> Warning: Supplied argument is not a valid MySQL result resource in
> /users/infoserv/web/register/ca/admin/catads.php on line 54
> 
> from:
> <?
>      while($row = mysql_fetch_object($obj))
>          {
>        $scobj = mysql_db_query($dbname,"select * from subcategory
> where id=$row->subcategory");
>        $scrow = mysql_fetch_object($scobj);
>        $cobj = mysql_db_query($dbname,"select * from category where
> id=$scrow->category");//54
>        $crow = mysql_fetch_object($cobj);
> ?>
> 
> 
> any ideas, of course, are most appreciated. thank you and best,
addison
> --
> Addison Ellis
> small independent publishing co.
> 114 B 29th Avenue North
> Nashville, TN 37203
> (615) 321-1791
> addison@bellsouth.net
> info@smipco.com
> subsidiaries of small independent publishing co.
> info@gloabaldog.com
> info@momandpocentral.com



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