You forgot to close the { of the first if-statement. <? session_start(); if(!$HTTP_COOKIE_VARS["username"]) { /* The Cookie is not set, so load the page as if it is the first time */ include("library/include/header.php"); include("library/include/database.php"); /* Include a header file and a database connections/functions file */ ?> <form name="login" method="post" action=""> <select name="select"> <? $query = "SELECT * FROM Staff WHERE ResterauntId = 1"; $result = mysql_query($query) or die( mysql_error () ); While( $row = mysql_fetch_array($result) ) { ?> <option value="<? echo $row["0"]; ?>"><? echo $row["1"]; echo $row["2"]; ?></option> <? } ?> </select> </form> David Rice <haloplayer@hotmail.com> wrote@23.01.2003 20:53 Uhr: > When i run this script it tells me that I have a parse error on line 34? I > really can't see it anyhelp (please!) would be much appreciated Cheers, Dave > > <? > > session_start(); > > if(!$HTTP_COOKIE_VARS["username"]) { > > /* The Cookie is not set, so load the page as if it is the first time > */ > > include("library/include/header.php"); > include("library/include/database.php"); > > /* Include a header file and a database connections/functions file > */ > > ?> > > <form name="login" method="post" action=""> > <select name="select"> > > <? > > $query = "SELECT * FROM Staff WHERE ResterauntId = 1"; > $result = mysql_query($query) or die( mysql_error () ); > > While( $row = mysql_fetch_array($result) ) { > > ?> > <option value="<? echo $row["0"]; ?>"><? echo $row["1"]; echo > $row["2"]; ?></option> > <? > } > ?> > </select> > </form> > > _________________________________________________________________ > Stay in touch with MSN Messenger http://messenger.msn.co.uk > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php