Yes that makes sense, but it is pretty much the same thing I was doing and it's producing the same results. Its basically putting the first element in all 4 table cells. The thing is...I am only selecting from one field. Im trying to get the 4 elements of the column with each pass. So in essence I am trying to get the pointer to move down the array 4 positions within one pass through the loop. If I had any kind of logicl skills I probably could get it:) Art "Ryan Jameson" <RJameson@usa.ibs.org> wrote in message CC8578B824E74940BA5126774F49628D015A7E11@nathan.ibs.org">news:CC8578B824E74940BA5126774F49628D015A7E11@nathan.ibs.org... while ($ar = mysql_fetch_array($rs)) echo "<tr><td>". $ar['field1']."</td><td>".$ar['field2']."</td></tr>"; Make sense? -----Original Message----- From: Art Chevalier [mailto:arthurc@scn.spawar.navy.mil] Sent: Thursday, December 05, 2002 12:44 PM To: php-db@lists.php.net Subject: MySQL Array Hello, I am pulling one column out of a MySQL table in an array. I want to place each element into a HTML table 4 rows across. I am currently doing this with the mysql_fetch_array() function. How can I pull out 4 array elements in one pass through a while loop? Thanks Art Chevalier -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
