But what do all those $row['fieldname'} rows do? Call me ignorant (you wouldn't be the first), but a statement that simply has a variable name doesn't DO anything. Should these have echos in front of them? --- Adam Voigt <adam@cryptocomm.com> wrote: > Umm, he is putting them into an array, I quote: > > while ($row = mysql_fetch_array($result)) { > > > $row['Books.Title']; > > > $row['Books.Author']; > > > $row['Books.ISBN']; > > > $row['BookList.dbase']; > > > $row['BookList.dbase_user']; > > > $row['BoxSet.BoxSet']; > > > $row['Category.Category']; > > > $row['Category.Sub_category']; > > > $row['Publisher.Publisher']; > > > $row['AuthUsers.email']; > > > > > > } > > See the while condition? > > On Wed, 2002-11-27 at 06:03, Chris Barnes wrote: > > You need to put your $result into an array. you can use: > > > > $result_array = mysql_fetch_array($result); > > > > then, if you know the field names in the array, print them like > so: > > > > echo $result_array["field1"]; > > echo $result_array["field2"]; > > > > or if you dont know their names you can refer to their position > numbers > > starting from 0 e.g. > > > > echo $result_array[0]; > > echo $result_array[1]; > > > > using the position numbers you could put together a quick script > to > > crawl through the array and print all the fields with a few lines > of > > code. > > > > On Wed, 2002-11-27 at 05:09, The Cossins Fam wrote: > > > Hello. > > > > > > I am using MySQL as a database for a departmental library. I > have written > > > a quick search script, but keep getting "resource id #2" as a > result to my > > > search. I have read the online documentation for the > > > mysql_fetch_array() function and must say, I don't see that I'm > missing > > > anything. However, I've only started programming, much less > working with > > > PHP, so perhaps someone can help me out. Here's my code: > > > > > > <? > > > > > > $quickSearch = "mcse"; > > > > > > $table1 = "Books"; > > > $table2 = "BookList"; > > > $table3 = "BoxSet"; > > > $table4 = "Category"; > > > $table5 = "Publisher"; > > > $table6 = "AuthUsers"; > > > $table7 = "CD"; > > > > > > $connection = mysql_connect("localhost", "root") or > die("Couldn't connect > > > to the library database."); > > > > > > $db_select = mysql_select_db("library", $connection) or > die("Couldn't > > > select the library database."); > > > > > > $search = "SELECT * FROM $table1 LEFT JOIN $table2 ON > Books.BookListID = > > > BookList.BookListID > > > LEFT JOIN $table3 ON Books.BoxSetID = BoxSet.BoxSetID > > > LEFT JOIN $table4 ON Books.CategoryID = > Category.CategoryID > > > LEFT JOIN $table5 ON Books.PublisherID = > Publisher.PublisherID > > > LEFT JOIN $table6 ON Books.auID = AuthUsers.auID > > > LEFT JOIN $table7 ON Books.CD = CD.CD_ID > > > WHERE Books.Title LIKE \"%'$quickSearch'%\" > > > OR Books.Author LIKE \"%'$quickSearch'%\" > > > OR Books.ISBN LIKE \"%'$quickSearch'%\" > > > OR BookList.dbase LIKE \"%'$quickSearch'%\" > > > OR BookList.dbase_user LIKE \"%'$quickSearch'%\" > > > OR BoxSet.BoxSet LIKE \"%'$quickSearch'%\" > > > OR Category.Category LIKE \"%'$quickSearch'%\" > > > OR Category.Sub_category LIKE \"%'$quickSearch'%\" > > > OR Publisher.Publisher LIKE \"%'$quickSearch'%\""; > > > > > > $result = mysql_query($search, $connection) or die("Couldn't > search the > > > library."); > > > > > > while ($row = mysql_fetch_array($result)) { > > > $row['Books.Title']; > > > $row['Books.Author']; > > > $row['Books.ISBN']; > > > $row['BookList.dbase']; > > > $row['BookList.dbase_user']; > > > $row['BoxSet.BoxSet']; > > > $row['Category.Category']; > > > $row['Category.Sub_category']; > > > $row['Publisher.Publisher']; > > > $row['AuthUsers.email']; > > > > > > } > > > > > > > > > ?> > > > > > > I then have some HTML to display the result of the search. I > don't > > > receive any error messages - I just see an empty table from the > HTML > > > code I wrote. I added an echo of the $result to find the > "resouce id > > > #2". > > > > > > Thanks for any help you can provide. > > > > > > --joel > > > > > > > > > > > > > > > > > > > > > > > > > _________________________________________________________________ > > > The new MSN 8: advanced junk mail protection and 2 months FREE* > > > > http://join.msn.com/?page=features/junkmail > > > > > > > > > -- > > > PHP Database Mailing List (http://www.php.net/) > > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > > > -- > Adam Voigt (adam@cryptocomm.com) > The Cryptocomm Group > My GPG Key: http://64.238.252.49:8080/adam_at_cryptocomm.asc > > ATTACHMENT part 2 application/pgp-signature name=signature.asc ===== Mark Weinstock mark_weinstock@yahoo.com *************************************** You can't demand something as a "right" unless you are willing to fight to death to defend everyone else's right to the same thing. -Stolen from the now-defunct Randy's Random mailing list. *************************************** __________________________________________________ Do you Yahoo!? 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