The problem there is that you've got $a[$year] getting set a bunch of
times. That is busted code. $a[$year] will only contain the LAST value.
Replace that line with this one.
$a[] = array(year=>$year, value=>$value);
OR
$a[$i] = array(year=>$year, value=>$value);
Now $a[0][year] = 2002
Now $a[0][value] = 320
And on and on.
Peter
On 13 Nov 2002, Marco Tabini wrote:
> Perhaps I don't understand what it is you're looking for, but...
>
> $a = array();
> for ($i = 0; $i < $maxvalue; $i++)
> {
> $a[$year] = $value;
> }
>
> but this is almost too simple, which probably just means I didn't quite
> understand your question.
>
>
> Marco
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> On Wed, 2002-11-13 at 19:28, Martin Allan Jensen wrote:
> > Sorry fellers....
> >
> > Allready figured it out....sorry....now i see that the question was foolish....
> >
> > Anyway now i need help with something else...
> >
> > I now have some values:
> > 320 - 250 - 290 - 100
> > And years that fits to them:
> > 2002 - 2003 - 2004 - 2005
> >
> > How can i put these dynamic values in a array..... be carefull cause i need the array to be filled active in a loop, so i CAN only define ONE year, and ONE value in each LOOP!
> >
> > THANKS!!!
> >
> >
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