First create this array before you do anything:
$max = array(10=>1,
20=>1,
40=>1,
60=>1,
320=>1,
780=>1,
890=>1,
920=>1);
$year[2002] = $max;
$year[2003] = $max;
$i = 0;
while(list($a,$b)=each($v)) {
$year[$y[$i]][$v[$i]] = 0;
}
reset($year);
while(list($a,$b)=each($year)) {
while(list($c,$d)=each($b)) {
if ($d == 1) $next[$a][$c]=1;
}
}
At this point $next will be a two dimensional array IF all the V's in a
year are not used up. If they are, $next[2002] for example will be
!isset($next[2002]).
To get your $Y and $V:
reset($next);
while(list($a,$b)=each($next)) {
$leftoveryears[] = $a;
while(list($c,$d)=each($b)) {
$leftovervalues[] = $c;
}
}
Now $leftoveryears is an array of years and $leftovervalues is an array of
values.
I would highly recommend using a single multi-dimensional array instead of
blind indexing for your year to value pairs. IE:
$pairs[2002][10] = 1; // (if set)
Peter
On Mon, 11 Nov 2002, Martin Allan Jensen wrote:
> Hi evryone....i have a problem that i hope you can help me with.
>
> Here it goes!
>
> I have two arrays one called "y" adn one called "v"
> Togeather they hold a year(Y) and a value(V)
>
> The array looks like this:
>
> v:
> 10
> 20
> 40
> 60
> 320
> 780
> 890
> 920
>
> y:
> 2002
> 2002
> 2002
> 2002
> 2002
> 2003
> 2003
> 2003
>
> ---------
>
> V represents a climping value
> Y represents the year of the value
> --------------------------------
>
> So the values 10, 20, 40, 60, 320 etc. grows until a new year is reachet. And then it schould start again in the new year.
> So MAXIMUM ONE VALUE PER YEAR....
>
> How can i make it return this out of the earlier menchent array :
>
> (Arrays)
> Y:
> 2002
> 2003
>
> V:
> 320
> 920
>
> So much thanks people....i tried now for two days and i just can't come up with anything...
>
> P.S. Sorry for my bad english!
>
> Martin Allan Jensen
>
>
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>
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Peter Beckman Systems Engineer, Fairfax Cable Access Corporation
beckman@purplecow.com http://www.purplecow.com/
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