I would suggest doing a var_dump of $order_index and see what is in
there.
Plus, you should take out the values in the form arrays...
Just do:
name="order_index[]"
On Thu, 2002-11-07 at 15:24, Aaron Wolski wrote:
> Hi All,
>
>
> In a form I have checkboxes associated with order records. The
> checkboxes are for deleting order records (should a client choose to do
> so).
>
> It looks like this:
>
> <form name="form" action="process_bank.php" method="POST">
> <input type="hidden" name="order_index[0]" value="1">
> <td class="cartlink" align="center"><input type="checkbox"
> name="delete[0]" value="1"></td>
> <input type="hidden" name="order_index[1]" value="3">
> <td class="cartlink" align="center"><input type="checkbox"
> name="delete[1]" value="1"></td>
> <input type="hidden" name="order_index[2]" value="8">
> <td class="cartlink" align="center"><input type="checkbox"
> name="delete[2]" value="1"></td>
> <input type="hidden" name="order_index[3]" value="12">
> <td class="cartlink" align="center"><input type="checkbox"
> name="delete[3]" value="1"></td>
> </form>
>
> Now.. when the process button is pressed the information is carried off
> to the process_bank.php script.
>
> Lets assume for this example.. I selected the checkbox delete[0] (which
> equals value 1) and delete[3] (which equals value 12).
>
> In the script I have this code:
>
> for ($i=0;$i<sizeof($order_index);$i++) {
>
> $orderQuery = db_query("SELECT id FROM TestOrderTable WHERE
> id=".$order_index[$i]);
> $orderResult = db_fetch($orderQuery);
>
> if ($delete[$i] == 1) {
>
> $ids .= $orderResult["id"];
>
> echo $ids;
>
>
> }
> }
>
> The echo'd value that I get is 1,1,12 when it should be 1,12.
>
> When only ONE checkbox is selected I just get the one value displayed
> (i.e. if I selected the first checkbox the echo'd value would be 1).
>
> Does anyone know why the first value is being duplicated on a multiple
> select but not on a single select?
>
> Sorry if this sounds confusing :(
>
> Aaron
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