I think you have forgotten that the variable $tbn2 is not available in your
function, unless you include it into your function, using the "global"
statement.
Try this code:
function getnames(){
global $tbn2;
$gnlistsql = "select name from $tbn2";
$gnlistres = mysql_query($gnlistsql);
while($nlist = mysql_fetch_array($gnlistres)){
$nlistop = "<option value=\"$nlist[name]\">$nlist[name]</option>";
$nlistsel = "<select name=\"getname\">$nlistop</select>";
echo $nlistsel;
}
}
"Dave Carrera" <dave@davecarrera.com> wrote in message
000001c276be$4d93a260$759e27d9@phpdevbox001">news:000001c276be$4d93a260$759e27d9@phpdevbox001...
> Hi All
>
> I have created a function and insde that function it dose a standard
> select, fetch_arry, while loop.
>
> I get a error from mysql saying not a vaild resource but if I take the
> statemnet out of the function all works fine and dandy.
>
> Are there things I should be aware of when trying to include mysql
> statements inside a function?
>
> I have include my code here if it helps.
>
> function getnames(){
> $gnlistsql = "select name from $tbn2";
> $gnlistres = mysql_query($gnlistsql);
> while($nlist = mysql_fetch_array($gnlistres)){
> $nlistop = "<option value=\"$nlist[name]\">$nlist[name]</option>";
> $nlistsel = "<select name=\"getname\">$nlistop</select>";
> echo $nlistsel;
> }
> }
>
> There error is reported back in the while line...
>
> Any help or advice is appreciated as always.
>
> P.S reason for the fuction is that I will call the select a name list a
> few times so I thought of making it a function then calling it when
> needed.
>
> Thank You
>
> Dave C
>
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