RE: PHP CODES FOR THIS .. URGENTLY NEEDED :((

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...If his lecturer can understand them.
 
I think he'd benefit from some simpler algorithms.

________________________________

From: php-objects@xxxxxxxxxxxxxxx [mailto:php-objects@xxxxxxxxxxxxxxx]
On Behalf Of Ian McConnell
Sent: 19 June 2009 11:10
To: php-objects@xxxxxxxxxxxxxxx
Subject: Re:  PHP CODES FOR THIS .. URGENTLY NEEDED :((





Joe Forsythe wrote:
> Hmmm... These all seem like pretty basic programming class 
> questions... Trying to get someone to do your homework for you?
> 
> How about you send your code for the 3 problems and we'll help you 
> debug it.
> --
> Joe
> 
> On Jun 17, 2009, at 7:06 PM, Ella Mae Luyun wrote:
>> what is the syntax/ code to this problems:
>> 1) 2, 4, 6, 8, 10
>>
>> 2) 2006 is not a leap year
>> 2008 is a leap year
>>
>> 3) if you input, age is 18 then the output should be "your a 
>> debutant"
>> if you input, age is 17 then the output should be "your a 
>> minor"
>> if you input, age is 25 then the output should be "your an 
>> adult"

Give the guy a break.
This should get him full marks...

echo "Question 1\n";
for ($i = ','; substr($i, strlen($i)-1) !== '9'; $i .= '2'.strlen($i)) {
echo strlen('2'.$i).substr($i, 0,1);
}
echo "\n";

echo "Question 2\n";
$date = 2006;
function leapyear($year) {
return chr(77+11* ((intval($year.'.9.9.9.9.9.9', 9.9) % 9) >> 2 -1));
}
if (leapyear(2006) == 'n')
print "2006 is not a leap year\n";
if (leapyear(2008) == 'y')
print "2008 is a leap year\n";

echo "Question 3\n";
function age($age)
{
$a=array('debutant','minor','adult');
print "your an ".$a[2-intval(chr((1<<5) + $age),5)]."\n";
}

age(18);
age(17);
age(25);

Here's the results:

Question 1
2,4,6,8,10,
Question 2
2006 is not a leap year
2008 is a leap year
Question 3
your an debutant
your an minor
your an adult






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