I can give you some hint. maybe it will be a good start for you 1 - You might want to use a loop. First define the variable and increase your varible by 2 while you are in the loop. When you reach last index get out of the loop. 2. just search for how to find a leap year. date function will help and also , just mod with 400 and 4. it will give answer of whether it is leap year or not. 3. if i understand correctly this is a form. define a variable that passes the parameter form an input box. then you should use conditions like if or case. if the check the value for 17, 18 , 25 and print the result according to the conditions i hope these hints helps your homework. On Fri, Jun 19, 2009 at 12:09 AM, Larry Helms <larr_helms@xxxxxxxxx> wrote: > > > --- In php-objects@xxxxxxxxxxxxxxx <php-objects%40yahoogroups.com>, > "ellamae.luyun" <ellamae.luyun@...> wrote: > > > > what is the syntax/ code to this problems: > > 1) 2, 4, 6, 8, 10 > > > > 2) 2006 is not a leap year > > 2008 is a leap year > > > > 3) if you input, age is 18 then the output should be "your a debutant" > > if you input, age is 17 then the output should be "your a minor" > > if you input, age is 25 then the output should be "your an adult" > > > > Um... we're here to help you with PROBLEMS... NOT DO your homework for you. > > This is like programming 101 stuff... you just have to figure out the > proper syntax for it. > > > [Non-text portions of this message have been removed]
