I think this code will help you. I believe you like to get the data form de vars for connection.
This the code for my_vars.inc:
<?php
$host = 'localhost';
$user = 'root';
$pwd = '';
$db = 'dvd';
?>
Here is my code so far;
<?php
// $file = "data.inc";
include("data.inc");
$format = "%c%cphp";
$first=60;
$second=63;
printf($format, $first,$second) ;
$information = $information. "\$host=' $server'; \n";
$information = $information. "\$user=' $user';\n" ;
$information = $information. "\$pwd='$ pwd';\n";
$information = $information. "\$dv='$db' ;\n";
echo $information;
?>
"Atkinson, Robert" <ratkinson@xxxxxxxxxxxxx> escribió:
Michael - I can't see any obvious problems with your code. What does data.inc
look like - does it contain the right information?
Robert.
________________________________
From: php-objects@xxxxxxxxxxxxxxx on behalf of Michael Reaves
Sent: Wed 23/04/2008 20:01
To: php-objects@xxxxxxxxxxxxxxx
Subject: Include file
Group,
I am trying to create an include file that contains the info to connect to a
MySQL database. I need the file look like this;
<?php
$host = 'localhost';
$user = 'root';
$pwd = '';
$db = 'dvd';
?>
Here is my code so far;
<?php
$file = "data.inc";
$format = "%c%cphp";
$first=60;
$second=63;
printf($format,$first,$second);
$information = $information."\$host='$server';\n";
$information = $information."\$user='$user';\n";
$information = $information."\$pwd='$pwd';\n";
$information = $information."\$dv='$db';\n";
echo $information;
$fw = fopen($file,"w+") or die("Can't open file $file");
$fout = fwrite($fw,$information);
fclose($fw);
?>
I have tried char and printf. When I run this the <?php must be interpreted
as a new php file and nothing is output.
Any suggestions will be appreciated.
Michael J. Reaves, MS, MCP
Project Specialist
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