Hi,
thank you very much for your response.We tried to solve that problem by running but we got following warning
[Thu Dec 13 10:39:09 2007] [error] [client 127.0.0.1] PHP Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in F:\\Softwares\\php\\htdocs\\vijaya\\sample_111207.php on line 13
[Thu Dec 13 10:39:09 2007] [error] [client 127.0.0.1] PHP Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in F:\\Softwares\\php\\htdocs\\vijaya\\sample_111207.php on line 15
Please give us correct solution...
Pradeep Rawat <rawat167@xxxxxxxxx> wrote: <?php
$mysql = mysql_connect
("localhost", "root", "abcd", "empdb");
$res_new=array();
$Query1="";$Query="";$result1=0;
$url="sciencedaily.com";
$Query1="call GetExpert_last('$url')";
echo $Query1;
echo "<br/>";
$res = $mysql->query("$Query1");
if(mysqli_num_rows($res)>0)
{
$row = mysql_fetch_row($res);
$res = $row[0];
$res_new[] = $row[0];
$res_new[] = $row[1];
//$mysqli->close();
//$res=NULL;
*********$Query="call GetExpert_lastvalue($res)";
echo $Query;echo "<br/>";
$result1=5;
$result1=$mysql->query("$Query");
echo "hai";echo "<br/>";
echo $result1;
if(mysql_num_rows($result1)>0)
{
$expert_value= mysql_fetch_row($result1);
$res_new[]=$expert_value[0];
$res_new[]=$expert_value[1];
$res_new[]=$expert_value[2];
} else
{
$res_new[]="None";
}
}
for($i=0;$i<count($res_new);$i++)
{
$strid= $res_new["$i"];
echo $strid;
echo "<br/>";
}
?>
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