Try
$myvar->squareit(11);
echo "Result is " . $myvar->myb;
In the code you supplied, $tclass is never defined, but because you
using it like an object (with the OO call '->'), PHP guesses its
type, which is why you get the result OBJECT.
However, if you called echo $myvar, you'd get the same result, as you
are only referencing the object itself, not a property of it. To get
any sensible answers, access the class variables.
Hope that helps,
Brian
--- In php-objects@yahoogroups.com, John Garvin <jgarvin@g...> wrote:
>
> Hi,
> I'm getting confused here. Perhaps someone could point me to an
> appropriate section of the manual?
>
> I have a class defined like so:
> <?php
> class tclass {
> var $mya;
> var $myb;
>
> function tclass() {
> $this->mya = "";
> $this->myb = "";
> }
> function & squareit($mya) {
> $this->myb = ($this->mya * $this->mya);
> return $this->myb;
> }
> }
> ?>
>
> and I'm calling it like this:
> <?php
> require('tclass.php');
>
> $myvar = new tclass;
> $tclass->squareit(11);
>
> echo "result is $tclass";
> ?>
>
> it outputs "result is Object".
> When I include the function 'squareit' in a script without the oo
> stuff, I get the result I expect.
> What am I missing?
>
> Thanks very much.
>
> --
> jpg
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