Re: Ajax query

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I am sorry, I missed that you are trying to use jQuery. 

I have never used jQuery. I have always delt directly with
the builtin ajax related code, which does not have to be
loaded.

JK

> On Sep 8, 2023, at 5:30 PM, Anthony Pulse <inland14@xxxxxxxx> wrote:
> 
> I know it may come as a surprise but this line should work
> 
> <Timed delay="5000" Ajax="url" insert="divTarget">
> 
>  If you need a call back just add the attribute callback="function" wherein the returned info is the parameter. Parameterizing it is taken care of already for you. $ git Clone https://GitHub.com/wise-penny/pipes If you want to see some of this kinda work, go-to g0d.me/pipes
> 
> Get Outlook for Android
> From: JEFFRY KILLEN <jekillen@xxxxxxxxxxx>
> Sent: Friday, September 8, 2023 8:18:56 PM
> To: gordonisnz@xxxxxxxxx <gordonisnz@xxxxxxxxx>
> Cc: php-general <php-general@xxxxxxxxxxxxx>
> Subject: Re: Ajax query
>  
> You do not need to "load" ajax. The object is built into Javascript. But there a newer versions
> that the xmlHttpRequestObject.
> 
> In general, your ajax request must be initiated by a user event such as mouse click or a keydown
> event. So that has to be written in. Also there is a sequence for intiating the ajax request that must
> be adhered to. THEN, on the server side there has to be PHP or other serverside code to recognize
> and handle the request and return a response if there should be one. The last phase if there is a 
> response expected is for Javascript to handle the response.
> 
> Mostly, the ajax request is done ASYNCRONISTICALLY. That just means that a response will NOT
> cause the browser window to reload. So state can be maintained. In technical terms it means that
> the request is done outside of the browsers main thread. 
> 
> A page initiating the request can process its response. But that is tricky to program.
> It essentially means that the PHP that process the request must exist above the
> DTD declaration and 'exit' as soon as it completes the request. It must also call
> header() and issue a header indicating the type of response: text, json, whatever.
> Then it uses print or echo to sent the response body. Then exit must called to prevent
> any html from being generated.
> 
> 1 header()
> 2 print (or echo) response body
> 3 exit
> 
> The newer version of asyncronous requests is more difficult and less intuitive.
> 
> Here is the result of a Google search for Javascript training.
> 
> https://www.google.com/search?client=firefox-b-1-d&q=Javascript+training
> 
> Here is another for mozilla javascript:
> https://www.google.com/search?q=mozilla+javascript&client=firefox-b-1-d&sca_esv=563870670&ei=T7X7ZOWYCa-n0PEPr-eMwAg&oq=mozilla&gs_lp=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&sclient=gws-wiz-serp
> 
> javascript ajax:
> https://www.google.com/search?q=javascript+ajax&client=firefox-b-1-d&sca_esv=563870670&ei=8rj7ZODYHY7G0PEP7JiYyAI&oq=javascript+ajax&gs_lp=Egxnd3Mtd2l6LXNlcnAiD2phdmFzY3JpcHQgYWpheCoCCAAyCBAAGIoFGJECMggQABiKBRiRAjIFEAAYgAQyBRAAGIAEMgUQABiABDIFEAAYgAQyBRAAGIAEMgUQABiABDIFEAAYgAQyBRAAGIAESKmVBVD5pARY9-sEcAh4AZABAJgBcaAB5AmqAQQxNS4xuAEByAEA-AEBwgIKEAAYRxjWBBiwA8ICChAAGIoFGLADGEPCAg4QABjkAhjWBBiwA9gBAcICGRAuGIoFGMcBGNEDGNQCGMgDGLADGEPYAQLCAhAQLhiKBRjIAxiwAxhD2AECwgIHEAAYDRiABMICBhAAGAcYHsICExAAGA0YgAQYsQMYgwEYsQMYgwHCAg0QABgNGIAEGLEDGIMBwgIKEAAYDRiABBixA8ICDRAAGIoFGA0YsQMYgwHCAgcQABiKBRhDwgINEAAYigUYsQMYgwEYQ8ICChAAGIoFGLEDGEPCAgsQABiABBixAxiDAcICDhAAGIoFGLEDGIMBGJECwgILEAAYigUYsQMYkQLCAggQABiABBixA8ICBxAAGIAEGArCAg0QABgWGB4YDxjxBBgKwgIIEAAYigUYhgPiAwQYACBBiAYBkAYRugYGCAEQARgJugYGCAIQARgI&sclient=gws-wiz-serp
> 
> > On Sep 8, 2023, at 4:27 PM, gordonisnz@xxxxxxxxx wrote:
> > 
> > Hello. I'm trying to get a "simple" ajax going, but the half-dozen examples I've tried do not work.
> > 
> > It Should simply run/activate a PHP script every 5 or 10 seconds, then display the output in the specified DIV. 
> > 
> > however, when I go to the developer tools, it says there is something wrong with the ajax line 
> > (and nothing changes on my screen) 
> > 
> > 
> > Stupid query 1:
> >   <link rel="stylesheet" href="/css/font-awesome.min.css" />
> > 
> > Do I need to 'load' Ajax somehow - like Javascript ? I do not see this in ANY examples/tutorials I see.
> > 
> > EXAMPLES:-
> > 
> > Here are 2 examples I've tried (apparently these are accepted answers to other peoples queries)
> > 
> > I did the full https://domain.com/rotatestats.php  and /rotatestats.php  - still same problem.
> > 
> > ONE:
> > 
> > <script type="text/javascript">
> > setInterval(function()  
> > {
> >         $.ajax( "/rotatestats.php" ).done(function(res) { <<< PROBLEM LINE
> >             document.getElementById("rot").innerHTML = res;
> >     })
> > 
> > }, 
> >  3000);
> > </script>
> > 
> > =================
> > 
> > TWO :-
> > 
> > <script type="text/javascript">
> > function updateShouts(){
> >     // Assuming we have #shoutbox
> >     $('#rot').load('rotatestats.php');  << PROBLEM LINE
> > }
> > setInterval( "updateShouts()", 10000 );
> > </script>
> > {/literal}
> >   <div id="rot">
> >   NEW:
> > 
> >   </div>
> > 
> > END EXAMPLES
> > 
> > ERROR MESSAGE IN DEVELOPER TOOLS:
> > Uncaught ReferenceError: $ is not defined
> >     at updateShouts (*WORD*:358:5)
> >     at <anonymous>:1:1
> > 
> > The WORD is some HTML output I do previous to the script. its NOT part of the script / div.. 
> > apparently it IS refreshing - which is good, but the output isn't appearing
> > 
> > 
> > Are these two nearly there? I'm not sure what the problem is with the PHP script. if I go to the script directly, it displays a random number..  (Once I get it going, I'll fix up the script to do what I want.
> > 
> > 
> > Gordon.




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