Re: Catch line indetation

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On 29.10.2016 at 09:45, Narcis Garcia wrote:

> El 28/10/16 a les 15:15, Christoph M. Becker ha escrit:
>
>> On 28.10.2016 at 13:09, Ashley Sheridan wrote:
>>
>>> On 28 October 2016 12:01:16 BST, Narcis Garcia <informatica@xxxxxxxxx> wrote:
>>>
>>>> Hello, I have a string (I quote here only) as:
>>>>
>>>> '   <table>...</table>'
>>>>
>>>> As you can see there are 3 spaces at the beginning, but it could be 0
>>>> or
>>>> 4 or any number of spaces.
>>>> How can I get a string with only the initial spaces part?
>>>>
>>>> '   <table>...</table>' -> '   '
>>>> 'hello' -> ''
>>>> ' hello' -> ' '
>>>>
>>>> Thanks.
>>>
>>> Have you tried regular expressions? Something like:
>>>
>>> ^( )*[^ ]
>>>
>>> The first captured match is the number of spaces, from 0 to any amount. Not the space between the brackets and before the closing square bracket
>>
>> Shouldn't that be
>>
>>   ^( *)[^ ]
>>
>> instead?
> 
> preg_replace('^( *)[^ ]', '${1}', '   <table>...</table>');
> Warning: preg_replace(): Unknown modifier ']'

Of course, the pattern has to be enclosed by delimiters, so you could use:

  preg_replace('/^( *)[^ ]/', '${1}', '   <table>...</table>')

-- 
Christoph M. Becker

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