El 28/10/16 a les 15:19, Curtis Maurand ha escrit: > Sorry for the top post. In the regex you can use ^\s*[*] which will catch any white space characters. > > On October 28, 2016 8:51:35 AM EDT, Richard <inbound-lists-php@xxxxxxxxxxxxxxxxxxxxx> wrote: >> >> >>> Date: Friday, October 28, 2016 12:09:31 +0100 >>> From: Ashley Sheridan <ash@xxxxxxxxxxxxxxxxxxxx> >>> >>> On 28 October 2016 12:01:16 BST, Narcis Garcia >>> <informatica@xxxxxxxxx> wrote: >>>> Hello, I have a string (I quote here only) as: >>>> >>>> ' <table>...</table>' >>>> >>>> As you can see there are 3 spaces at the beginning, but it could >>>> be 0 or >>>> 4 or any number of spaces. >>>> How can I get a string with only the initial spaces part? >>>> >>>> ' <table>...</table>' -> ' ' >>>> 'hello' -> '' >>>> ' hello' -> ' ' >>>> >>>> Thanks. >>> >>> Have you tried regular expressions? Something like: >>> >>> ^( )*[^ ] >>> >>> The first captured match is the number of spaces, from 0 to any >>> amount. Not the space between the brackets and before the closing >>> square bracket >>> >> >> You need to take into consideration that "whitespace" can be created >> by more than the simple "space" (ascii 32) character. A "[horizontal] >> tab" (ascii 9) is common, but also look at the top of php trim >> function documentation: >> >> <http://php.net/manual/en/function.trim.php> >> >> to see the characters that it handles as "whitespace". While "trim" >> does the opposite of what you're after, you could likely use the >> ctype_space function to accomplish your need: >> >> <http://php.net/manual/en/function.ctype-space.php> >> >> e.g., by iterating through the string until it returns "false". Also, >> "strpos" could be useful. >> >> >> >> -- >> PHP General Mailing List (http://www.php.net/) >> To unsubscribe, visit: http://www.php.net/unsub.php > preg_replace('^\s*[*]', '${1}', ' <table>...</table>'); Warning: preg_replace(): No ending delimiter '^' found -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
