> 19 maj 2016 kl. 03:26 skrev 酷丁 <zsxx51@xxxxxxxxxx>: > > hi,everyone! > > > a problem has troubled me for a long time,I have searched ,but haven't found the answer. > some thing like this: > > > ---A.php > <?php > include 'b.php'; > echo 'test A.php';//because calling exit in b.php,so this can't be execute > ?> > > > ---B.php > <?php > exit("test B.php"); > ?> > > > I want to include b.php(b.php is a third library,but it will exit the script) but no die.I try to find some function that can execute b.php and not die a.php ,but I can't. > are there any other method can do this? > > > thk... Hi! You are including 'b.php', but the file is 'B.php'. Some systems have case sensitive filenames. That means that 'b.php' and 'B.php' are different files. The 'include' function only raises a warning if the files does’t exist. Change the line to "require 'b.php';" and see if you get some errors. Besides that, always check your error logs. /frank -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php