On 11/30/2015 3:33 PM, Ashley Sheridan wrote:
Maybe not, but it can be done that way. I never said it was correct. The right way would be to write a class and use the methods of that class to do what you need based on the choice made.$script_result = shell_exec('p7a.php'); There is a lot of useful information here once you get past the snide comments at the top. http://stackoverflow.com/questions/8450696/execute-a-php-script-from-another-php-script On 11/29/2015 11:36 PM, Ethan Rosenberg wrote:Dear List - Can you not call a PHP script from a form -- action = 'program.php'? In my hands it does not work... I have tried the following include program.php; later in the program ... form . . echo "<input type='hidden' name='next_step' value='step14' />"; . . . . switch ( $_POST['next_step'] ) { case 'step14': { P7a.php(); } } } //end Switch The result of this is that program.php runs at the start of the script, and step14 is never called. I am totally confused. If you need more details, please specify. TIA. Ethanshell_exec is *not* the right method here. As others have pointed out, it appears there's a lack of understanding about how the PHP stack works with regards to requests and logic.
-- Curtis Maurand curtis@xxxxxxxxxxx <mailto:curtis@xxxxxxxxxxx> 207-252-7748
